Prove that vector [ a x b , b x c , c x a ] = vector [ a , b , c ]^2 & Also, If vector (a x b) , vector (b x c) & vector (c x a) are coplanar - Sarthaks eConnect | Largest Online Education Community
Let x0 be the point of local maxima of f(x) = vector(a.(b x c)), where vector a = xi - 2j + 3k, vector b = -2i + xj - k and
![SOLVED: If a, b, and c are vectors and c is a scalar, then we have the following properties: 1.axb = -bXa 2. (ca) Xb = c(a X b) = aX (cb) SOLVED: If a, b, and c are vectors and c is a scalar, then we have the following properties: 1.axb = -bXa 2. (ca) Xb = c(a X b) = aX (cb)](https://cdn.numerade.com/ask_images/49f5858648194792906b6f8eaadd89c0.jpg)
SOLVED: If a, b, and c are vectors and c is a scalar, then we have the following properties: 1.axb = -bXa 2. (ca) Xb = c(a X b) = aX (cb)
![SOLVED: Prove the following identities using index notation a ' (b x c) a X (b X c) (a x b) . (c x d) c . (a x b) =b. (c x a) SOLVED: Prove the following identities using index notation a ' (b x c) a X (b X c) (a x b) . (c x d) c . (a x b) =b. (c x a)](https://cdn.numerade.com/ask_images/65fce0bf80894bf484b1c8bff62e2fbc.jpg)
SOLVED: Prove the following identities using index notation a ' (b x c) a X (b X c) (a x b) . (c x d) c . (a x b) =b. (c x a)
![SOLVED: Problem 1.2 Straight line connecting the tips of three vectors originating from point: Show that the tips of three vectors B, and € originating from common point lie along a straight SOLVED: Problem 1.2 Straight line connecting the tips of three vectors originating from point: Show that the tips of three vectors B, and € originating from common point lie along a straight](https://cdn.numerade.com/ask_images/5e8ceaf9d8be4e72880b46749ad3acf2.jpg)