![Acceleration of particle moving in straight line can be written as `a=(dv )/(dt)=v(dv)/(dx)`. From t - YouTube Acceleration of particle moving in straight line can be written as `a=(dv )/(dt)=v(dv)/(dx)`. From t - YouTube](https://i.ytimg.com/vi/srrYsPvS7ZM/maxresdefault.jpg)
Acceleration of particle moving in straight line can be written as `a=(dv )/(dt)=v(dv)/(dx)`. From t - YouTube
![SOLVED: 6) The Vauume clem en+ dv= dx-dy-d z Ka 4du) (hv v dv)(k,4dz)l = =/hukv: 6 da-dv-d 2 | 4 #. #l-du-dv.4? 1) dw,dv.dZ Jv (4i V 2) c) ( nd SOLVED: 6) The Vauume clem en+ dv= dx-dy-d z Ka 4du) (hv v dv)(k,4dz)l = =/hukv: 6 da-dv-d 2 | 4 #. #l-du-dv.4? 1) dw,dv.dZ Jv (4i V 2) c) ( nd](https://cdn.numerade.com/ask_images/cdfeac35e5ad43be9e127bcd880ba5dd.jpg)
SOLVED: 6) The Vauume clem en+ dv= dx-dy-d z Ka 4du) (hv v dv)(k,4dz)l = =/hukv: 6 da-dv-d 2 | 4 #. #l-du-dv.4? 1) dw,dv.dZ Jv (4i V 2) c) ( nd
Doubt: sir,i had solved this question by putting Vdv/dx=acc,and from the graph dv/dx=0,so on putting 0,acc becomes equal to 0...so i marked option 3 but it is incorrect.sir,please tell me the right
![Question Video: Finding an Expression That Represents the Rate of Change of a Cube's Volume Using Related Rates | Nagwa Question Video: Finding an Expression That Represents the Rate of Change of a Cube's Volume Using Related Rates | Nagwa](https://media.nagwa.com/280178362646/en/thumbnail_l.jpeg)
Question Video: Finding an Expression That Represents the Rate of Change of a Cube's Volume Using Related Rates | Nagwa
![SOLVED: Choose the correct chain rule formula 0 A dv dx v dy dx dq dy dq dv dx dv dy dx dq oy dq dv dy dv dx dy dq dv SOLVED: Choose the correct chain rule formula 0 A dv dx v dy dx dq dy dq dv dx dv dy dx dq oy dq dv dy dv dx dy dq dv](https://cdn.numerade.com/ask_images/f9dae998dd144600926099da3090506f.jpg)
SOLVED: Choose the correct chain rule formula 0 A dv dx v dy dx dq dy dq dv dx dv dy dx dq oy dq dv dy dv dx dy dq dv
![please explain a=dv/dt = dv/dx = dx/dt = dv/dx =adx=vdv - Physics - Motion In A Straight Line - 2651959 | Meritnation.com please explain a=dv/dt = dv/dx = dx/dt = dv/dx =adx=vdv - Physics - Motion In A Straight Line - 2651959 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/discuss_editlive/3079860/2012_07_12_18_12_11/mathmlequation2915202041970641358.png)