![SOLVED: (10 points) Use the definition of derivative to compute f' (x) given f(c) = Vi. Hint: from the formula a3 b3 = (a b)(a? + ab + b8) we get that SOLVED: (10 points) Use the definition of derivative to compute f' (x) given f(c) = Vi. Hint: from the formula a3 b3 = (a b)(a? + ab + b8) we get that](https://cdn.numerade.com/ask_images/519fe857ee054ce5b874e7421c1b8ec6.jpg)
SOLVED: (10 points) Use the definition of derivative to compute f' (x) given f(c) = Vi. Hint: from the formula a3 b3 = (a b)(a? + ab + b8) we get that
![Lmao these are so true 。 a×a×a=aaa = a a×b=ab 2 a2b2 = (ab) 2 2 32+3 aa=a 2x3 a3 + b3 = (a + b)(a2-ab + b2) a,-b, = (a-b)(2+ab + Lmao these are so true 。 a×a×a=aaa = a a×b=ab 2 a2b2 = (ab) 2 2 32+3 aa=a 2x3 a3 + b3 = (a + b)(a2-ab + b2) a,-b, = (a-b)(2+ab +](https://cdn.dopl3r.com//media/memes_files/lmao-these-are-so-true-aaaaaa-a-abab-2-a2b2-ab-2-2-323-aaa-2x3-a3-b3-a-ba2-ab-b2-a-b-a-b2ab-b2-a-b3-a3-3a2b-3ab2-b3-a-b3-a3-3a2b-3ab2-b3-a4-a3-a4-3-a-a2-b2-a-hdKpH.jpg)
Lmao these are so true 。 a×a×a=aaa = a a×b=ab 2 a2b2 = (ab) 2 2 32+3 aa=a 2x3 a3 + b3 = (a + b)(a2-ab + b2) a,-b, = (a-b)(2+ab +
![SOLVED: Use the identity below to complete the tasks: a3 - b3 = (a - b)(a + ab + b2) When using the identity for the sum of two cubes to factor SOLVED: Use the identity below to complete the tasks: a3 - b3 = (a - b)(a + ab + b2) When using the identity for the sum of two cubes to factor](https://cdn.numerade.com/ask_previews/76ac02d8-ba1a-49d5-b17c-4c85fbaba7c6_large.jpg)