In ∆ABC, if AC is greater than AB, then prove that AC AB is less than BC, AC BC is less than AB and BC AB is less than AC.
![geometry - In $\triangle ABC$ with $AB=AC$ and $\angle BAC=20^\circ$, $D$ is on $AC$, with $BC=AD$. Find $\angle DBC$. Where's my error? - Mathematics Stack Exchange geometry - In $\triangle ABC$ with $AB=AC$ and $\angle BAC=20^\circ$, $D$ is on $AC$, with $BC=AD$. Find $\angle DBC$. Where's my error? - Mathematics Stack Exchange](https://i.stack.imgur.com/O6Lat.png)
geometry - In $\triangle ABC$ with $AB=AC$ and $\angle BAC=20^\circ$, $D$ is on $AC$, with $BC=AD$. Find $\angle DBC$. Where's my error? - Mathematics Stack Exchange
![SOLVED: Expression a + 0 =a a+b=b+a Dual a . 1 =0 ab ba a+(b+c)=latb)tc a(bc) = (abc a + bc = Ka+ ba +c) a(b +c) = ab + ac a+6 = SOLVED: Expression a + 0 =a a+b=b+a Dual a . 1 =0 ab ba a+(b+c)=latb)tc a(bc) = (abc a + bc = Ka+ ba +c) a(b +c) = ab + ac a+6 =](https://cdn.numerade.com/ask_images/27d2cf9107834440955a2edaf77aafc2.jpg)
SOLVED: Expression a + 0 =a a+b=b+a Dual a . 1 =0 ab ba a+(b+c)=latb)tc a(bc) = (abc a + bc = Ka+ ba +c) a(b +c) = ab + ac a+6 =
![A is Invertible and AB = AC Prove B = C If A is Singular find 2 Matrices where AB =AC P 2-5-6 - YouTube A is Invertible and AB = AC Prove B = C If A is Singular find 2 Matrices where AB =AC P 2-5-6 - YouTube](https://i.ytimg.com/vi/POg6I5jcvFs/maxresdefault.jpg)
A is Invertible and AB = AC Prove B = C If A is Singular find 2 Matrices where AB =AC P 2-5-6 - YouTube
![∆ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (Fig 11.26). The height AD from A to BC, is 6 cm. Find the area of ∆ABC. ∆ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (Fig 11.26). The height AD from A to BC, is 6 cm. Find the area of ∆ABC.](https://d138zd1ktt9iqe.cloudfront.net/media/seo_landing_files/b1-1623827121.png)