![Bits : [P67] cos^3(2pi/7)+cos^3(4pi/7)+cos^3(8pi/7) (ARML, 2013)](https://latex.artofproblemsolving.com/3/1/5/3153f801b2813a10305223681c2f25c9b40f2bb4.png "Bits : [P67] cos^3(2pi/7)+cos^3(4pi/7)+cos^3(8pi/7) (ARML, 2013)")
Bits : [P67] cos^3(2pi/7)+cos^3(4pi/7)+cos^3(8pi/7) (ARML, 2013)
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)&line2=\mathrm{Solution:\:}\frac{%CF%80}{7} "arcsin(sin((6pi)/7))")
arcsin(sin((6pi)/7))
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SOLVED:Find the exact value of (a) sin^-1(sinπ/ 7) (b) sin^-1(sinπ) (c) sin^-1(sin5 π/ 7) (d) sin^-1(sin630)
\cos(\frac{%CF%80}{7})&line2=\mathrm{Solution:\:}0.78183%E2%80%A6 "2sin(pi/7)cos(pi/7)")
2sin(pi/7)cos(pi/7)
if sinxcos(pi/7)-sin(pi/7)cosx=-sqrt2/2 then x can equal? - Brainly.com
sin "" (pi)/(7) sin "" (2pi)/(7) sin "" (4pi )/(7)=
Evaluate sin ( pi6 + cos^-1 14 )
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Trigonometry Angles--Pi/7 -- from Wolfram MathWorld
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sin(3pi/7) cos(4pi/7))/sin(pi/7)` - YouTube
&line2=\mathrm{Solution:\:}\frac{\sqrt{2}(\sqrt{3}%2B1)}{4} "sin(7/12 pi)")
sin(7/12 pi)
What is cot((7pi/2)#? | Socratic
If cos(π/7),cos(3π/7),cos(5π/7) are roots of the equation 8x^3 4x^2 4x+1=0 ,then cos(π/14) cos(3π/14) cos(5π/14) is
the value of sin(pi/7)+sin((2pi)/7)+sin((3pi)/7) is
Sin 7pi/6 - Find Value of Sin 7pi/6 | Sin 7π/6
